block.gp.pos

Syntax

v/f = block.gp.pos(bgpp<,i>)

Get the position of a gridpoint.

Returns:v or f - position vector or component
Arguments:bgpp - block gridpoint pointer i - optional index of component

Component Access

f = block.gp.pos.x(bdpp)

Get the \(x\)-component of the position.

Returns:f - \(x\)-component of the position vector
Arguments:bggp - gridpoint pointer
f = block.gp.pos.y(bdpp)

Get the \(y\)-component of the position.

Returns:f - \(y\)-component of the position vector
Arguments:bggp - gridpoint pointer
f = block.gp.pos.z(bdpp)

Get the \(z\)-component of the position.

Returns:f - \(z\)-component of the position vector
Arguments:bggp - gridpoint pointer