block.gp.pos
Syntax
- v/f = block.gp.pos(bgpp<,i>)
Get the position of a gridpoint.
Returns: v or f - position vector or component Arguments: bgpp - block gridpoint pointer i - optional index of component
Component Access
- f = block.gp.pos.x(bdpp)
Get the \(x\)-component of the position.
Returns: f - \(x\)-component of the position vector Arguments: bggp - gridpoint pointer
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