struct.node.disp.local

Syntax

m = struct.node.disp.local(sn<,i>)

Get the displacement of structure node expressed in a local system.

Returns:

m - matrix of displacement with all degrees-of-freedom if the argument i is not assigned, or displacement at the ith degree-of-freedom if the argument i is assigned.

Arguments:

sn - pointer to the structure node

i - degree-of-freedom, i ∈ {1, 2, … , 6}. The default is 1.