struct.node.mass.local

Syntax

f = struct.node.mass.local(sn<,i>)

Get the mass at the degree-of-freedom i ∈ {1, 2, … , 6} of in the node-local system.

Returns:

v - mass mass at the degree-of-freedom

Arguments:

sn - structure node pointer

i - degree-of-freedom, i ∈ {1, 2, … , 6}. The default is 1.