struct.pile.load

Syntax

v = struct.pile.load(p)

struct.pile.load(p) = v

Get/set the uniform applied distributed load acting on the pile element in the local \(y\)- and \(z\)-directions.

The \(x\)-component of the return value will always be 0.0; on assignment it is ignored.

Returns:v - the uniform applied distributed load acting on the pile element Accepts:v - the uniform applied distributed load acting on the pile element Arguments:p - a pointer to a pile element