Hydraulic Fracture
Note
To view this project in 3DEC, use the menu command . The main data files used are shown at the end of this example. All data files are found in the project.
Problem Statement
The propagation of a vertical hydraulic fracture constrained within a 20 m thick horizontal layer is analyzed. Fluid with a 1 cP (10^{−3} pa × s) viscosity is injected through the vertical borehole at the total rate of 2 × 10^{−3} m^{3}/s, uniformly distributed over the thickness of the layer. The fracture propagates in a homogeneous, isotropic elastic medium with a Young’s modulus of 10 GPa, and a Poisson’s ratio of 0.2.
Warning
This problem takes a long time to run. When running this verification problem, allow 1224 hours (depending on computer speed) for the calculation to complete.
Analytical Solution
The evolution of the pressures and fracture widths in this problem can be approximated by the PKN solution (Perkins and Kern 1961) under the following assumptions:
linear elastic fracture mechanics (LEFM) theory is applicable;
the pressure gradient in the direction of fracture propagation is created by the flow resistance in a narrow elliptically shaped channel;
the fracture has a fixed height, \(H\), independent of the distance from the wellbore, \(x\);
in any vertical elliptical crosssection perpendicular to the direction of propagation, the fluid pressure, \(p\), is constant (i.e., no vertical pressure drop);
at the tip of the fracture \(p_{net}\) = 0 (i.e., the fracturing fluid pressure is equal to confining stress, \(\sigma_c\), at the crack tip); and
planestrain deformation occurs in the vertical cross sections – each identical vertical section acts independently (only valid if \(L\) >> \(H\)).
The geometry of the PKN model and the important model variables are illustrated in Figure 1.
According to the PKN solution (Perkins and Kern 1961), the net pressure, \(p_{net}\), can be approximated using the following expression:
while the expression for the width (aperture) in the middle of the fracture is
where \(E\) is the Young’s modulus, \(\nu\) is the Poisson’s ratio, \(q\) is the injection rate, \(\mu\) is the viscosity of the injected fluid, and \(L\) and \(H\) are the length and height of the fracture, respectively, as illustrated in Figure 1.
3DEC Model
The 3DEC model uses the symmetry of the problem and represents one (upper) half of the fracture only. The trace of the fracture is predefined in 3DEC by the vertical contact plane, which is initially joined together but allowed to open (fracture) only within the constantheight layer during the simulation as dictated by stress changes induced by the injected fluid. (The vertical contact plane is not allowed to fracture outside the predefined layer.) The fracture plane is the only discontinuity within the model. The PKN solution is for a fracture in an infinite elastic medium. Because the 3DEC model size must be finite, it is selected to be sufficiently large compared to the size of the fracture (i.e., fracture height, \(H\), and the fracture length, \(L\), achieved during the simulation) such that the deformation of the fracture is not affected by the model size, but also considering the effects on the model runtime (because too large of a model would require long simulation time). The model geometry is illustrated in Figure 2. The discretization of the model, shown in Figure 3, illustrates the graded mesh with the finest discretization of 1 m zone size near the fracture and the coarsest discretization of 4 m zone size away from the fracture, along the farfield boundaries.
“Roller” boundary conditions were applied on all outside boundaries of the mechanical model. The fluid was injected at the specified rate along the vertical edge of the fracture surface as indicated in Figure 2.
Results and Discussion
After 368 s of injection, the fracture was approximately 75 m long, which was considered sufficient to satisfy the assumption (i.e., \(L/H\) = 75/20 = 3.75 >> 1) used in derivation of the PKN solution. At the state after 368 s of injection, the 3DEC results are compared with the PKN solution. The state of the 3DEC model is illustrated by the contour plots of displacements, fluid pressure, and apertures shown in Figures 4 through 6, respectively. The fluid pressure contours in Figure 5 illustrate that there is no pressure gradient in the vertical direction, except near the injection point and the fracture tip, as approximated by the PKN solution.
The net pressure profile, as calculated in 3DEC, is shown in Figure 7. The fracture widths (apertures) predicted in 3DEC and using the PKN solution are compared in Figure 8. Overall, the 3DEC predictions are in reasonably good agreement with the PKN solution. The match of the maximum widths is particularly good near the injection point. As expected, the discrepancy is greatest near the fracture tip. 3DEC uses constant strain zones of uniform size along the entire fracture. Thus, the approximation in the 3DEC model of the stress singularity and strain gradients near the fracture tip is relatively poor. The second reason for the poor match near the fracture tip is that the minimum fracture aperture in the 3DEC model cannot be smaller than the userspecified residual aperture. The motivation for this limit is to prevent model instability when the flow equations become singular as the aperture decreases to zero. Typically, the residual aperture is selected to be a small value compared to prevailing apertures in the model. In these simulations, the residual aperture was assumed to be 50 \(\mu m\). Comparisons of the maximum net pressure and fracture widths as calculated using 3DEC and the PKN solution are provided in Table 1. The match is good, with an error less than 7%.
PKN 
3DEC 
Error (%) 


w(0) (mm) 
1.039 × 10^{−3} 
1.037 × 10^{−3} 
0.2 
p(0) (Pa) 
2.71 × 10^{5} 
2.89 × 10^{5} 
6.6 
Reference
Perkins, T., and L. Kern. “Widths of hydraulic fractures,” J. Pet. Tech., 222, pp. 937949 (1961).
Data Files
pkn.dat
; file: pkn.dat
; example of hydraulic fracturing
model new
model random 10000
;
fish automaticcreate off
model configure fluidflow
model largestrain off
fish define geometry
global fractureLength = 10.0
local modelWidth = 8.*fractureLength
local modelHeight = 3.*fractureLength
local modelLength = 10.*fractureLength
global x1 = 0.5*modelWidth
global x12 = 0.25*modelWidth
global x2 = 0.
global x21 = 0.2*fractureLength
global x22 = 0.2*fractureLength
global x23 = 0.25*modelWidth
global x3 = 0.5*modelWidth
global y1 = 0.
global yh1 = 0.25*modelLength
global yh = 0.5*modelLength
global yh2 = 0.75*modelLength
global y2 = modelLength
global z1 = 0.
global z2 = fractureLength
global z21 = z2+0.2*fractureLength
global z3 = modelHeight
global edge1 = 0.1*fractureLength
global edge2 = 0.2*fractureLength
global edge3 = 0.4*fractureLength
global edgelength = edge1
global z1l = z10.2*edge
global z2l = z20.2*edge
global z2h = z2+0.2*edge
global z3h = z3+0.2*edge
global x2l = x20.2*edge
global x2h = x2+0.2*edge
global y1l = y10.2*edge
global y1h = y1+0.2*edge
end
[geometry]
block create brick [x1] [x3] [y1] [y2] [z1] [z3]
block cut jointset dip 0 dipdirection 0 origin [x2] [y1] [z21]
block cut jointset dip 90 dipdirection 90 origin [x2] [y1] [z1]
block cut jointset dip 90 dipdirection 0 origin [x2] [yh] [z1]
block cut jointset dip 90 dipdirection 0 origin [x2] [yh1] [z1]
block cut jointset dip 90 dipdirection 0 origin [x2] [yh2] [z1]
block cut jointset dip 90 dipdirection 90 origin [x12] [y1] [z1]
block cut jointset dip 90 dipdirection 90 origin [x23] [y1] [z1]
block hide range plane dip 0 dipdirection 0 origin [x2] [y1] [z21] above
block cut jointset dip 90 dipdirection 90 origin [x21] [y1] [z1]
block cut jointset dip 90 dipdirection 90 origin [x22] [y1] [z1]
block hide range plane dip 90 dipdirection 90 origin [x21] [y1] [z1] below
block hide range plane dip 90 dipdirection 90 origin [x22] [y1] [z1] above
block cut jointset dip 0 dipdirection 0 origin [x2] [y1] [z2]
block hide off
;
block hide range plane dip 90 dipdirection 90 origin [x2] [y1] [z2] above
block join on
block hide off
block hide range plane dip 90 dipdirection 90 origin [x2] [y1] [z2] below
block join on
block hide off
block zone generate edgelength [edge1] ...
range positionx [x21] [x22] positionz [z1] [z21]
block zone generate edgelength [edge2] range positionx [x12] [x23]
block zone generate edgelength [edge3]
;
model save 'pknzoned'
model restore 'pknzoned'
;
block gridpoint apply velocityx 0. range positionx [x1]
block gridpoint apply velocityx 0. range positionx [x3]
block gridpoint apply velocityy 0. range positiony [y1]
block gridpoint apply velocityy 0. range positiony [y2]
block gridpoint apply velocityz 0. range positionz [z1]
block gridpoint apply velocityz 0. range positionz [z3]
;
[global pois_ = 0.2]
[global E_ = 1e10]
block zone cmodel assign elastic
block zone property density 2600. young [E_] poiss [pois_]
block contact jmodel assign mohr
block contact property stiffnessnormal 1e9 ...
stiffnessshear 1e9 ...
cohesion 1e4 ...
tension 1e4
flowplane vertex property apertureinitial 0.5e4 ...
apertureminimum 0.5e4 ...
aperturemaximum 1e2
block contact property stiffnessnormal 1e10 ...
stiffnessshear 1e10 ...
tension 1e30 ...
cohesion 1e30 ...
range positionz [z2l] [z3h]
flowplane vertex property apertureinitial 1e4 ...
apertureminimum 1e4 ...
aperturemaximum 1e4 ...
range positionz [z2l] [z3h]
block fluid crackflow on
;
[global visc_=1e3]
[global inj_=2e3]
block fluid property bulk 2e7
block fluid property density 1000.
block fluid property viscosity [visc_]
; injecting into half of fracture, so discharge is injection rate/length/2
flowplane edgelength apply discharge [inj_/fractureLength/2.0] ...
range positionx [x2l] [x2h] ...
positiony [y1l] [y1h] ...
positionz [z1l] [z2h]
;
model mechanical active on
model fluid active on
;model fluid follower on
;model fluid substep 10
model mechanical follower on
model mechanical substep 1
model solve fluid timetotal 368
model save 'pkn'
;
program call 'PKN_verify'
;
program return
pkn_verify.dat
; file pkn_verify.dat
;
;
[global frac_length = 75.0]
[global frac_height = 20.0]
;
; analytical solution forigin aperture and pressure
; along y axis
; aperture stored in table '1'
; pressure stored in table '3'
;
fish define _analytical
; pressure from PKN solution
local numerator_ = 16.0*visc_*inj_*E_*E_*E_*frac_length
local denominator_ = (1.0pois_*pois_)^3*math.pi*frac_height^4
local pressure_ = math.sqrt(math.sqrt(numerator_/denominator_))
loop foreach local gp_ block.gp.list
local z_ = block.gp.pos.z(gp_)
if z_ < 0.01
local y_ = block.gp.pos.y(gp_)
if y_ < 75.1
; aperture eqn from PKN solution
local aperture_=3*((visc_*inj_*(1pois_^2)*(frac_lengthy_))/E_)^0.25
table(1,y_) = aperture_
table(3,y_) = pressure_
endif
endif
end_loop
end
;
; 3DEC aperture and pressure along y axis
; aperture stored in table '2'
; pressure stored in table '4'
;
fish define _3DEC
loop foreach local fpe_ flowplane.vertex.list
local coord_global = flowplane.vertex.pos(fpe_)
if comp.z(coord_global) < 0.01
local y_ = comp.y(coord_global)
if y_ < 75.1
local aperture_ = flowplane.vertex.aperture.hydraulic(fpe_)
table(2,y_) = aperture_
local knot_ = flowplane.vertex.knot(fpe_)
local pressure_ = flowknot.pp(knot_)
table(4,y_) = pressure_
endif
endif
end_loop
end
;
[_analytical]
[_3DEC]
table '1' label 'Aperture analytical'
table '2' label 'Aperture 3DEC'
table '3' label 'Pressure analytical'
table '4' label 'Pressure 3DEC'
Endnote
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