geom.node.start.index
Syntax
- i = geom.node.start.index(n)
Get local index i of point n within the first edge attached to the point. This can be used to iterate through all edges attached to a node with the
geom.node.start.edge
,geom.edge.next.edge
andgeom.edge.next.index
functions.Returns: i - node index with 1 \(\le\) i \(\le\) 2 Arguments: n - node pointer
Usage Example
The following example illustrates how geom.node.start.index
can be used to iterate through all edges attached to a node, counting the number of edges.
global test21 = geom.edge.node.pos(pnt,2)
global test22 = geom.edge.pos(pnt)
; Test node to edge loop
global test23 = 0
local node_pnt = geom.node.find(setpnt,1)
local edge_pnt = geom.node.start.edge(node_pnt)
local node_ind = geom.node.start.index(node_pnt)
io.out(edge_pnt)
io.out(node_ind)
loop while edge_pnt # null
test23 = test23 + 1
local next_pnt = geom.edge.next.edge(edge_pnt,node_ind)
node_ind = geom.edge.next.index(edge_pnt,node_ind)
edge_pnt = next_pnt
io.out(edge_pnt)
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